- A152
- B142
- C124
- D162
Solution:
In the above binomial expansion, the terms at the odd position will get eliminated.
We would be left with
$2({^{5}}\text{C}_{1}(\sqrt{3})^{4}+{^5}\text{C}_{3}(\sqrt{3})^{2}+{^5}\text{C}_{5})$
$=2(5(3^2)+10(3)+1)$
$=2(45+30+1)$
$=2(76)$
$=152$
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