MCQ
Standing waves are produced in a $10 \mathrm{~m}$ long stretched string. If the string vibrates in $5$ segments and the wave velocity is $20 \mathrm{~m} / \mathrm{s}$, the frequency is
  • A
    $2 \mathrm{~Hz}$
  • B
    $4 \mathrm{~Hz}$
  • $5 \mathrm{~Hz}$
  • D
    $10 \mathrm{~Hz}$

Answer

Correct option: C.
$5 \mathrm{~Hz}$
String vibrates in five segment so $\frac{5}{2} \lambda=l \Rightarrow \lambda=\frac{2 l}{5}$
Hence $n=\frac{v}{\lambda}=5 \times \frac{v}{2}l=5\times\frac{20}{2}\times10=5\mathrm{~Hz}$

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