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Study of Gas Laws — CHEMISTRY STD 9 — Question

ICSE BoardEnglish MediumSTD 9CHEMISTRYStudy of Gas Laws5 Marks
Question
State Charles's law.
✓

Answer

Charles's Law
At constant pressure, the volume of a given mass of a dry gas increases or decreases by $1 / 273^{\text {rd }}$ of its original volume at $0^{\circ} \mathrm{C}$ for each degree centigrade rise or fall in temperature.
$\mathrm{V} \propto \mathrm{T}$ (at constant pressure)
At temperature $T_1(\mathrm{~K})$ and volume $\mathrm{V}_1\left(\mathrm{~cm}^3\right)$ :
$\mathrm{V}_1 \propto \mathrm{T}_1 \text { or } \frac{\mathrm{V}_1}{\mathrm{~T}_1}=\mathrm{K}=\text { constant...(i) }$
At temperature $T_2(\mathrm{~K})$ and volume $\mathrm{V}_2\left(\mathrm{~cm}^3\right)$ :
$\mathrm{V}_2 \propto \mathrm{T}_2 \mathrm{or} \frac{\mathrm{V}_2}{\mathrm{~T}_2}=\mathrm{K}=$ constant....(ii)
From (i) and (ii),
$\frac{\mathrm{V}_1}{\mathrm{~T}_1}=\frac{\mathrm{V}_2}{\mathrm{~T}_2}=\text { constant }$
For Temperature $=$ Conversion from Celsius to Kelvin
$1 \mathrm{~K}={ }^{\circ} \mathrm{C}+273$
Example:$20^{\circ} \mathrm{C}=20+273=293 \mathrm{~K}$

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