Question
State First law of thermodynamics.

Answer

According to first law of thermodynamics when some quantity of heat (dQ) is supplied to a system capable of doing external work, then quantity of heat absorbed by the system (dQ) is equal to sum of increase in internal energy of system (dU) due to rise in temperature and external work done by system (dW) in expansion i.e.
dQ = dU + dW

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Why are space rockets usually launched from west to east in the equatorial plane?
Do you expect the gas in a cooking gas cylinder to obey the ideal gas equation?
State if the following statements is true or false. Give reasons for your answer:
Work done in the motion of a body over a closed loop is zero for every force in nature.
Give an example of:
A physical quantity which has a unit but no dimensions.
The thermal energy developed in a current-carrying resistor is given by U = i2 Rt and also by U = Vit. Should we say that U is proportional to i2 or i?
A porter carried a box on the roof of a bus in 5 minutes. The second porter loaded the same box in 2 minutes. Which porter did more work?
The sign of work done by a force on a body is important to understand. State carefully if the following quantities are positive or negative:
Work done by an applied force on a body moving on a rough horizontal plane with uniform velocity.
Fig. depicts four x-t plots for linear motion of a particle. Which of the plots represent periodic motion? What is the period of motion (in case of periodic motion)?

Why two layers of cloth of equal thickness provide warmer covering than a single layer of cloth of double thickness?
In a rotating body, $\text{a}=\alpha\text{r}$ and $\text{v}=\omega\text{r}.$ Thus $\frac{\text{a}}{\alpha}=\frac{\text{v}}{\omega}.$ Can a co you use the theorems of ratio and proportion studied in algebra so as to write
$\frac{\text{a}+\alpha}{\text{a}-\alpha}=\frac{\text{v}+\omega}{\text{v}-\omega}$