Question
State one feature by which the phenomenon of interference can be distinguished from that of diffraction.
A parallel beam of light of wavelength $600 \ nm$ is incident normally on a slit of width ‘a’. If the distance between the slit and the screen is $0.8 m$ and the distance of $2nd$ order maximum from the centre of the screen is $15 \ mm$, calculate the width of the slit.

Answer

The given features:-
Interference Diffraction
  1. Fringes of equal width
Fringes of unequal width
  1. Fringes of equal intensity
Fringes of decreasing intensity
  1. Due to superposition of two waves (wavefronts)
Due to superposition of secondary wavefronts.
  1. Maximal at $\theta =\frac{\lambda}{\text{a}}$
Minima at $\theta = \frac{\lambda}{\text{a}}$
$\text{ (Numerical : Formula}\text{ y} =\frac{(2\text{n} + 1)\lambda\text{D}}{2\text{a}}\text{ or } \frac{5\lambda\text{D}}{2\text{a}}$
Substitution and Result: $8 \times 10^{–5} m$ or $0.08 \ mm.$

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