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Electrolysis — Chemistry STD 10 — Question

ICSE BoardEnglish MediumSTD 10ChemistryElectrolysis2 Marks
Question
State the reason for difference in product formed at anode during electrolysis of copper sulphate using copper and platinum as anode.
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Answer

When copper is used as anode, it being an active anode ionises to form copper ions which enter the solution.
Cu - 2e- → Cu2+
Thus, its mass continuously decreases.
When platinum is used as anode, it being inert anode does not ionise. Instead amongst the SO42- and OH- ions, the later discharge at anode to liberate oxygen gas.
4OH- - 4e- → 2H2O + O2

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