Question
State the truth value of (p ˄ ∼p)
| p | ∼p | p ∧ ∼p |
| T | F | F |
| F | T | F |
Truth value of (p ˄ ∼p) is F.
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$e^x\left(\frac{1}{x}-\frac{1}{x^2}\right)$
