MCQ
Strongest nucleophile in polar protic solvent is
- A${F^\Theta }$
- B${Cl^\Theta }$
- ✓${I^\Theta }$
- D${Br^\Theta }$
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$C _{2} H _{6} \rightarrow C _{2} H _{4}+ H _{2}$
the reaction enthalpy $\Delta_{ r } H =...........{ kJ\, mol ^{-1}}$.
(Round off to the Nearest Integer).
[Given : Bond enthalpies in $kJ$ $mol$ $^{-1}:C-C : 347, C = C : 611 ; C - H : 414, H - H : 436]$
