Question
Suggest a way to determine $10 m$ value of water.
$
\lambda_{ m }^{\circ}\left( H _2 O \right)=\lambda_{ H ^{+}}^{\circ}+\lambda_{ OH ^{-}}^{\circ}
$

Answer

We find out
$\lambda_{ m }^{\circ}( HCl ), \lambda_{ m }^{\circ}( NaOH )$ and $\lambda_{ m }^{\circ}( NaCl )$
Then
$
\lambda_{ m }^{\circ}\left( H _2 O \right)=\lambda_{ m }^{\circ}( HCl )+\lambda_{ m }^{\circ}( NaOH )-\lambda_{ m }^{\circ}( NaCl )
$

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