MCQ
Sulphur has highest oxidation state in
- A$S{O_2}$
- ✓${H_2}S{O_4}$
- C$N{a_2}{S_2}{O_3}$
- D$N{a_2}{S_4}{O_6}$
$\mathop {{H_2}S{O_4}}\limits^ * = + 6$
$\mathop {N{a_2}{S_2}{O_3}}\limits^{\,\, * } = + 2$
$\mathop {N{a_2}{S_4}{O_6}}\limits^{\,\, * } = + \frac{5}{2}$.
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$I.\,SeO_3^{2 - } + BrO_3^ - + {H^ + } \to SeO_4^{2 - } + B{r_2} + {H_2}O$
$II.\,BrO_3^ - + AsO_2^ - + {H_2}O \to B{r^ - } + AsO_4^{3 - } + {H^ + }$
