MCQ
Sulphur in $+3$ oxidation state is present in
- ASulphurous acid
- BPyrosulphuric acid
- ✓Dithionous acid
- DThiosulphuric acid
$HO - \mathop {\mathop S\limits^{||} }\limits^O - \mathop {\mathop S\limits^{||} }\limits^O - OH$ ;
$2( + 1) + 2x + 4( - 2) = 0$
$2x = 8 - 2 = 6$;
$x = +3$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

${C_6}{H_5} - N{H_2}\xrightarrow[{HCl}]{{NaN{O_2}}}A\xrightarrow{{CuCN}}B\xrightarrow{{{H_2}/Ni}}C\xrightarrow{{HN{O_2}}}D$
product $(D)$ would be
${K}_2 \mathrm{Cr}_2 \mathrm{O}_7$ & ${CuSO}_4$
SideX $SPM$ Side $\mathrm{Y}$ Due to osmosis :