MCQ
Sulphur on boiling with $NaOH$ solution gives
- A$N{a_2}{S_2}{O_3} + NaHS{O_3}$
- ✓$N{a_2}{S_2}{O_3} + N{a_2}S$
- C$N{a_2}S{O_3}$$ + {H_2}S$
- D$N{a_2}S{O_3} + S{O_2}$
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$NO(g) + Br_2 (g) \rightleftharpoons NOBr_2 (g)$
$NOBr_2(g)+ NO(g) \longrightarrow 2NOBr(g)$
If the second step is the rate determining step, the order of the reaction with respect to $NO(g)$ is
Method $1\,:\,$ $RBr\xrightarrow[diethyl\,\,ether]{Mg}RMgBr\xrightarrow[2.\,{{H}_{3}}{{O}^{+}}]{1.\,C{{O}_{2}}}RC{{O}_{2}}H$
Method $2\,:\,$ $RBr\xrightarrow{NaCN}RCN\xrightarrow[heat]{{{H}_{2}}O,HCl}RC{{O}_{2}}H$
Which one of the following statements correctly describes this conversion ?
