Download App

BINOMIAL THEOREM — MATHS STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceMATHSBINOMIAL THEOREM1 Mark
MCQ
Sum of the coefficients of $(1+x)^n$ is always a:
  • ✓
    An integer
  • B
    Positive integer
  • C
    Negative integer
  • D
    Zero
✓

Answer

Correct option: A.
An integer
  1. An integer
Solution:
To determine the sum of coefficients, we substitute $\mathrm{x}=1$ in the above expression.
Thus sum of coefficients $=(1+1)^n=2^n$
Hence, its a positive integer.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from BINOMIAL THEOREM→BINOMIAL THEOREM — all question types→MATHS STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The circle $x^2+y^2-3 x-4 y+2=0$ cuts x-axis:
→
The equation of three circles are ${x^2} + {y^2} - 12x - 16y + 64 = 0,$ $3{x^2} + 3{y^2} - 36x + 81 = 0$ and ${x^2} + {y^2} - 16x + 81 = 0.$ The co-ordinates of the point from which the length of tangent drawn to each of the three circle is equal is
→
Two functions f and g are said to be equal if:
→
The ellipse $E_1: \frac{x^2}{9}+\frac{y^2}{4}=1$ is inscribed in a rectangle $R$ whose sides are parallel to the coordinate axes.

Another ellipse $E _2$ passing through the point $(0,4)$ circumscribes the rectangle $R$.. The eccentricity of the ellipse $E _2$ is

→
The value of $x$ that satisfies the relation $x = 1 - x + x^2 - x^3 + x^4 - x^5 + ......... \infty$
→
If a circle whose centre is $(1, -3)$ touches the line $3x - 4y - 5 = 0$, then the radius of the circle is
→
The number of ways, $16$ identical cubes, of which $11$ are blue and rest are red, can be placed in a row so that between any two red cubes there should be at least $2$ blue cubes, is
→
The partial fractions of ${{{x^4} + 24{x^2} + 28} \over {{{({x^2} + 1)}^3}}}$ are
→
If equation of a line is y = 3x - 4 then find the slope of line:
→
The lines

$(p - q)x + (q - r)y + (r - p) = 0$

$(q - r)x + (r - p)y + (p - q) = 0$

$(r - p)x + (p - q)y + (q - r) = 0$  are

→