Question
System of linear equation 5x + ky = 5, 3x + 3y = 5 is consistent, if :

Answer

(D) System of linear equation is consistent if
$
\begin{aligned}
\left|\begin{array}{cc}
5 & k \\
3 & 3
\end{array}\right| & \neq 0 \\
15-3 k & \neq 0 \\
3 k & \neq 15 \\
k & \neq 5
\end{aligned}
$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The equation of the plane passing through (2, −3, 1) and is normal to the line joining the points (3, 4, −1) and (2, −1, 5) is given by:
  1. x + 5y − 6z + 19 = 0
  2. x − 5y + 6z − 19 = 0
  3. x + 5y + 6z + 19 = 0
  4. x − 5y − 6z − 19 = 0
The derirative of $\sin ^2 x$ with respect to $x$ is-
The eqution of the plane $\vec{\text{r}}=\hat{\text{i}}-\hat{\text{j}}+\lambda(\hat{\text{i}}+\hat{\text{j}}+\hat{\text{k}})+\mu(\hat{\text{i}}-2\hat{\text{j}}+3\hat{\text{k}})$ in scalar product from is:
  1. $\vec{\text{r}}.(5\hat{\text{i}}-2\hat{\text{j}}-3\hat{\text{k}})=7$
  2. $\vec{\text{r}}.(5\hat{\text{i}}+2\hat{\text{j}}-3\hat{\text{k}})=7$
  3. $\vec{\text{r}}.(5\hat{\text{i}}-2\hat{\text{j}}+3\hat{\text{k}})=7$
  4. $\text{None of these}$
The direction ratios of the diagonal of the cube joining the origin to the opposite corner are $($when the $3$ concurrent edges of the cube are coordinate axes$).$
The projection of a directed line segment on the co-ordinate axes are 12, 4, 3, then the direction cosines of the line are:
Given a curve $y=7 x-x^3$ and $x$ increases at the rate of 2 units per second. The rate at which the slope of the curve is changing, when $x=5$ is
The value of $\sin\bigg[\cos^{-1}\Big(\frac{7}{25}\Big)\bigg]$ is:
  1. $\frac{25}{24}$
  2. $\frac{25}{7}$
  3. $\frac{24}{25}$
  4. $\frac{7}{24}$
The binary operation $^*$ is defined by $a ^* b = a^2 + b^2 + ab + 1,$ then $(2 ^* 3) ^* 2$ is equal to$:$
The solution of $\frac{\text{dy}}{\text{dx}}+\frac{\text{y}}{\text{x}}=\frac{1}{\sqrt{1+\text{x}^2}}$ is:
  1. $\text{y}=\frac{1+\text{x}^2}{\text{x}}+\frac{\text{c}}{\text{x}}$
  2. $\text{y}=\frac{\sqrt{1+\text{x}^2}}{\text{x}}+\frac{\text{c}}{\text{x}}$
  3. $\text{y}=\frac{\text{x}}{\sqrt{1+\text{x}^2}}+\text{cx}$
  4. $\text{None of these}$
If $x + y = 3$ and $xy = 2,$ then the value of $x^3 - y^3$ is equal to.