MCQ
$\tan \,{20^o}\cot \,{10^o}\cot \,{50^o}$ is equal to
- A$\frac{1}{{\sqrt 3 }}$
- ✓$\sqrt 3 $
- C$\frac{{\sqrt 3 }}{4}$
- D$4\sqrt 3 $
$\tan \theta \tan (60-\theta) \tan (60+\theta)=\tan 3 \theta$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| $x_i$ | $0$ | $1$ | $5$ | $6$ | $10$ | $12$ | $17$ |
| $f_i$ | $3$ | $2$ | $3$ | $2$ | $6$ | $3$ | $3$ |