Question
$\tan A + \cot (180^\circ + A) + \cot (90^\circ + A) + \cot (360^\circ - A)$

Answer

a
(a) $\tan A + \cot (180^\circ + A) + \cot (90^\circ + A) + \cot (360^\circ - A)$

$ = \tan A + \cot A - \tan A - \cot A = 0$.

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