MCQ
$\tan \left( {\frac{\pi }{4} + \theta } \right) - \tan \left( {\frac{\pi }{4} - \theta } \right) = $
- ✓$2\tan 2\theta $
- B$2\cot 2\theta $
- C$\tan 2\theta $
- D$\cot 2\theta $
$= \frac{{1 + \tan \theta }}{{1 - \tan \theta }} - \frac{{1 - \tan \theta }}{{1 + \tan \theta }}$
$ = \frac{{4\tan \theta }}{{1 - {{\tan }^2}\theta }} $
$= 2\left( {\frac{{2\tan \theta }}{{1 - {{\tan }^2}\theta }}} \right) $
$= 2\tan 2\theta $.
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