MCQ
Temperature dependent equation can be written as
- ✓$\ln \,k = \ln A - {e^{{E_a}/RT}}$
- B$\ln k = \ln A + {e^{{E_a}/RT}}$
- C$\ln k = \ln A - {e^{RT/{E_a}}}$
- DAll of these
$K = A{e^{ - {E_a}/RT}}$
$\ln K = \ln A - {e^{{E_a}/RT}}$
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$2NO + Br \to 2NOBr$ is
$NO + Br_2 \rightleftharpoons NOBr_2$ (Fast)
$NOBr_2 + NO \to 2NOBr$ (Slow)
The rate law expression is