MCQ
The addition of $HBr$ is easiest with
- A$ClC{H_2} = CHCl$
- B$ClCH = CHCl$
- C$C{H_3} - CH = C{H_2}$
- ✓${(C{H_3})_2}C = C{H_2}$
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$(I)$ electron affinity of $Y$ is high $(II)$ ionization energy of $X$ is low
$(III)$ lattice energy of $XY$ is high $(IV)$ lattice energy of $XY$ is low
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