MCQ
The alcohol which does not give a stable compound on dehydration is
- AEthyl alcohol
- ✓Methyl alcohol
- C$n-$propyl alcohol
- D$n-$butyl alcohol
To form alkene, we need at least two carbon atoms. But, methanol $\left( CH _3 OH \right)$ has only one carbon atom. So, it does not give a stable compound on dehydration.
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$\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}}\\
|\\
{C{H_3} - C - OH}\\
|\\
{\,\,\,\,\,\,\,C{H_3}}
\end{array}}\limits_{\rm{I}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}}\\
|\\
{C{H_3} - CH - OH}
\end{array}}\limits_{{\rm{II}}} $ $\mathop {C{H_3} - C{H_2} - OH}\limits_{{\rm{III}}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,Ph}\\
|\\
{C{H_3} - C - OH}\\
|\\
{\,\,\,\,\,\,\,{\kern 1pt} C{H_3}}
\end{array}}\limits_{{\rm{IV}}} $

