- ✓Acidic
- BBasic
- CNeutral
- DAmphoteric
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(I)\,\,\,\,{N_2} + 2{O_2} \rightleftharpoons 2N{O_2}$
$(II)\,\,\,\,2N{O_2} \rightleftharpoons {N_2} + 2{O_2}$
$(III)\,\,\,\,N{O_2} \rightleftharpoons \frac{1}{2}{N_2} + 2{O_2}$
The correct relation from the following is
'$X$ ' and ' $Y$ ' respectively are :
Reason : $F -F$ bond has low bond dissociation energy.
${X_{\left( s \right)}} + Y_{\left( {aq} \right)}^{ + 2} \rightleftharpoons {Y_{\left( s \right)}} + X_{\left( {aq} \right)}^{2 + }$
Given :
$E_{{x^{ + 2}}/x}^o = - 1.36\,volt$ ;
$E_{{y^{ + 2}}/y}^o = - 0.76\,volt\,\frac{{2.303\,RT}}{F} = 0.06$
$CH_3COOH + PCl_5 \longrightarrow (A)$ $\xrightarrow[(2){{H}_{2}}O]{(1)\,C{{H}_{3}}MgBr}\left( B \right)$ Product $B$ would be