MCQ
The angle between the lines whose direction cosines satisfy the equations $l + m + n = 0$, ${l^2} + {m^2} - {n^2} = 0$ is given by
- A$\frac{{2\pi }}{3}$
- B$\frac{\pi }{6}$
- C$\frac{{5\pi }}{6}$
- ✓$\frac{\pi }{3}$
Solving above equations, we get $m = \pm \frac{1}{{\sqrt 2 }},\,\,n = \pm \frac{1}{{\sqrt 2 }}$ and $l = 0$.
$\therefore \,\,\,\theta = \frac{\pi }{3}$ or $\frac{\pi }{2}$.
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Then for the objective function $z=-x+2 y$
$(i)$ Maximum value of $z$ has at $\ldots \ldots \ldots . . .$
$(ii)$ Minimum value of $z$ has at $\ldots \ldots \ldots . . .$
$(iii)$ The maximum value of $z$ is $\ldots \ldots \ldots . . .$
$(iv)$ The minimum value of $z$ is $\ldots \ldots \ldots . . .$
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Column $A$
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Column $B$
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Maximum of $Z$
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$325$
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