MCQ
The angular frequency of motion whose equation is $4\frac{{{d^2}y}}{{d{t^2}}} + 9y = 0$ is ($y =$ displacement and $t =$ time)
  • A
    $2.25$
  • B
    $0.44$
  • $1.5$
  • D
    $0.67$

Answer

Correct option: C.
$1.5$
c
$4 \frac{d^{2} y}{d t^{2}}+9 y=0$

or $\frac{d^{2} y}{d t^{2}}=\frac{-9}{4} y$

Comparing with $SHM$ equation

$\frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dt}^{2}}=-\omega^{2} \mathrm{y}$

$\therefore \omega^{2}=\frac{9}{4}$

$\therefore \omega=\frac{3}{2}$

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