The angular velocity and the amplitude of a simple pendulum is $'\omega '$ and $'A'$ respectively. At a displacement $x$ from the mean position its kinetic energy is $'T'$ and potnetial energy is $'V'$. Then the ratio $\frac{V}{T}$ is
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$\mathrm{V}=\frac{1}{2} \mathrm{Kx}^{2}$
$\mathrm{T}=\frac{1}{2} \mathrm{K}\left(\mathrm{A}^{2}-\mathrm{x}^{2}\right)$
$\frac{V}{T}=\frac{x^{2}}{A^{2}-x^{2}}$
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