MCQ
The appropriate reagent for the transformation


- A$Zn(Hg),\,HCl$
- ✓$N{H_2}N{H_2}O{H^ - }$
- C${H_2}/Ni$
- D$NaB{H_4}$

but $HCl$ will also bring about dehydration of alcohol to form alkene. Therefore, appropriate reagent for the conversion is $N{H_2}N{H_2},\,\,O{H^ - }$.
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Glucose, Mannose, Galactose, $\alpha -$ Glucose, $\beta -$ Glucose
$(K)\,\, (L)\,\, (M)\,\, (N)\,\, (O)$
Correct set of epimer and anomer is respectivley
Epimer - Anomer

Phenol $\xrightarrow{{Zn\,\,dust}}X\,\xrightarrow[{Anhyd.\,AlC{l_3}}]{{C{H_3}Cl}}\,Y\xrightarrow{{Alkaline\,\,KMn{O_4}}}\,Z$
the product $Z$ is