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STD 12 - 8. Application and integration — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - 8. Application and integration4 Marks
MCQ
The area between the curve $y = 4 + 3x - {x^2}$ and $x -$ axis is
 
  • ✓
    $125/6$
  • B
    $125/3$
  • C
    $125/2$
  • D
    None of these
✓

Answer

Correct option: A.
$125/6$
a
(a) Solving $y = 0$ and $y = 4 + 3x - {x^2},$

we get $x = - 1,\,4$.

Curve does not intersect $x -$ axis between $x = - 1$ and $x = 4$.

$\therefore$ Area $ = \int_{ - 1}^4 {(4 + 3x - {x^2})dx = \frac{{125}}{6}} $.

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