The area between the curve y = 4 + 3x - x^2 and x - axis is - Vidyadip

MCQ

The area between the curve $y = 4 + 3x - {x^2}$ and $x -$ axis is

✓
$125/6$
B
$125/3$
C
$125/2$
D
None of these

✓

Answer

Correct option: A.

$125/6$

a
(a) Solving $y = 0$ and $y = 4 + 3x - {x^2},$

we get $x = - 1,\,4$.

Curve does not intersect $x -$ axis between $x = - 1$ and $x = 4$.

$\therefore$ Area $ = \int_{ - 1}^4 {(4 + 3x - {x^2})dx = \frac{{125}}{6}} $.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 8. Application and integration→8. Application and integration — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

The area (in square units) of the region enclosed by the ellipse $x^2+3 y^2=18$ in the first quadrant below the line $y=x$ is :

Let $R = \{(a, a)\}$ be a relation on a set $A$. Then $R$ is

The direction cosines of a line which is equally inclined to axes, is given by:

$\underline{+}\frac{1}{3}$
$\underline{+}\frac{1}{\sqrt{3}}$
$1$
$0$

The function f : A → B defined by f(x) = 4x + 7, x ∈ R is:

One-one
Many-one
Odd
Even

If $\text{y}=\log_\text{e}\Big(\frac{\text{x}}{\text{a}+\text{bx}}\Big)^\text{x}$ then $\text{x}^3\text{y}_2=$

$(\text{xy}_1-\text{y})^2$
$(1+\text{y})^2$
$\Big(\frac{\text{y}-\text{xy}_1}{\text{y}_1}\Big)^2$
$\text{None of these}$

The vector component of $\vec{\text{b}}$ perpendicular to $\vec{\text{a}}$ is:

$\big(\vec{\text{b}}.\vec{\text{c}}\big)\vec{\text{a}}$
$\frac{\vec{\text{a}}\times\big(\vec{\text{b}}\times\vec{\text{a}}\big)}{|\vec{\text{a}}|^2}$
$\vec{\text{a}}\times\big(\vec{\text{b}}\times\vec{\text{a}}\big)$
None of these

The least value of the function $F(x) = $ $\int_{5\pi /4}^x {(3\sin u + 4\cos u)\,du} $ on the interval $\left[ {\frac{{5\pi }}{4},\,\,\frac{{4\pi }}{3}} \right]$ is

The value of $\lambda $ for which the vectors $2\lambda i + j - k$ and $2j + k$ are perpendicular, is

Choose the correct answer in each of the following:
If A and B are any two events such that P(A) + P(B) – P(A and B) = P(A), then

P(B|A) = 1
P(A|B) = 1
P(B|A) = 0
P(A|B) = 0

If s = t³- 4t²+ 5 describes the motion of a particle, then its velocity when the acceleration vanishes, is:

$\frac{16}{2}\ \text{unit}/\text{sec}.$
$\frac{\text{-32}}{3}\ \text{unit}/\text{sec}.$
$\frac{4}{3}\ \text{unit}/\text{sec}.$
$-\frac{16}{3}\ \text{unit}/\text{sec}.$