MCQ
The area of an equilateral triangle having side length equal to $\frac{3}{\sqrt{4}}\text{ cm}$ is:
- A$\frac{2}{27}\text{sq.}\text{cm}$
- B$\frac{2}{15}\text{sq.}\text{cm} $
- ✓$\frac{3}{16}\text{sq.}\text{cm}$
- D$\frac{3}{14}\text{sq.}\text{cm}$
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