MCQ
The area of an equilateral triangle with side $6 \sqrt{3} cm$ is
- A$27 cm^2$
- ✓$27 \sqrt{3} cm^2$
- C$18 \sqrt{3} cm^2$
- D$54 \sqrt{3} cm^2$
✓
Answer
Correct option: B.
$27 \sqrt{3} cm^2$
(b) $27 \sqrt{3} cm^2$
The area $A$ of an equilateral triangle with side $a$ unit is given by $A=\frac{\sqrt{3}}{4} a^2$.
Here, $a=6 \sqrt{3} cm$
$\therefore \quad A=\frac{\sqrt{3}}{4} \times(6 \sqrt{3})^2 cm^2=27 \sqrt{3} cm^2$
The area $A$ of an equilateral triangle with side $a$ unit is given by $A=\frac{\sqrt{3}}{4} a^2$.
Here, $a=6 \sqrt{3} cm$
$\therefore \quad A=\frac{\sqrt{3}}{4} \times(6 \sqrt{3})^2 cm^2=27 \sqrt{3} cm^2$
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