The argument of the complex number - 1 + i 3 is ............. ^ - Vidyadip

MCQ

The argument of the complex number $ - 1 + i\sqrt 3 $ is ............. $^\circ$

A
$-60$
B
$60$
✓
$120$
D
$-120$

✓

Answer

Correct option: C.

$120$

c
(c)$arg( - 1 + i\sqrt 3 ) = {\tan ^{ - 1}}\left( {\frac{{\sqrt 3 }}{{ - 1}}} \right) = {120^o}$
because it lies in second quadrant.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

If $A,\,B,\,C$ are the vertices of a triangle whose position vectors are $a, b, c $ and $G$ is the centroid of the $\Delta ABC,$ then $\overrightarrow {GA} + \overrightarrow {GB} \, + \overrightarrow {GC} $ is

The length of the perpendicular from the point $(2, -1, 4)$ on the straight line, $\frac{{x + 3}}{{10}} = \frac{{y - 2}}{{ - 7}} = \frac{z}{1}$ is

Let $f$ be a differentiable function in $\left(0, \frac{\pi}{2}\right)$ If $\int\limits_{\cos x}^{1} t^{2} f(t) d t=\sin ^{3} x+\cos x-1$ then $\frac{1}{\sqrt{3}} f^{\prime}\left(\frac{1}{\sqrt{3}}\right)$ is equal to

If $A$ is an invertible matrix of order $2,$ then ${{{\rm{A}}^{ - 1}}}$ is equal to

$\tan \left[ {{{\cos }^{ - 1}}\frac{4}{5} + {{\tan }^{ - 1}}\frac{2}{3}} \right] =$

Let $\vec{a}=\hat{i}+\alpha \hat{j}+\beta \hat{k}, \alpha, \beta \in R$. Let a vector $\vec{b}$ be such that the angle between $\vec{a}$ and $\vec{b}$ is $\frac{\pi}{4}$ and $|\vec{b}|^2=6$, If $\vec{a} \cdot \vec{b}=3 \sqrt{2}$, then the value of $\left(\alpha^2+\beta^2\right)|\vec{a} \times \vec{b}|^2$ is equal to

The equation of the lines joining the vertex of the parabola ${y^2} = 6x$ to the points on it whose abscissa is $24$, is

Let $p(x)=a_0+a_1 x+\ldots+a_n x^n$. If $p(-2)=-15$ $p(-1)=1, p(0)=7, p(1)=9, p(2)=13$ and $p(3)=25$, then the smallest possible value of $n$ is

The greatest coefficient in the expansion of ${(1 + x)^{2n + 1}}$ is

If $a,\;b,\;c$ are in $A.P.$, then ${10^{ax + 10}},\;{10^{bx + 10}},\;{10^{cx + 10}}$ will be in