- ALanthanoid contraction.
- BLanthanoid expansion.
- CActinoid contraction.
- DNone of these.
Explanation:
The atomic and ionic radii (M3+ ions) of Lanthanide elements decrease with increase in atomic number.
This effect is called Lanthanoid contraction. This is due to poor shielding of f electrons.
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$(A)$ The stronger the temperature dependence of the rate constant, the higher is the activation energy.
$(B)$ If a reaction has zero activation energy, its rate is independent of temperature.
$(C)$ The stronger the temperature dependence of the rate constant, the smaller is the activation energy.
$(D)$ If there is no correlation between the temperature and the rate constant then it means that the reaction has negative activation energy.
$\begin{align}
\begin{matrix}
C{{H}_{3}}-CH-C{{O}_{2}}H \\
|\,\,\,\,\,\,\,\, \\
\underset{\oplus }{\mathop{N}}{{H}_{3}} \\
\end{matrix}\,\,\,\,\,\,p{{K}_{a}}=2.2 \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,p{{K}_{b}}=4.4 \\
\end{align}$

$Ag| AgCl | KCl(1\,M) || KBr(1\,M) | AgBr | Ag$
Select the correct option -
(Assume $100\%$ ionization)
$A.$ $0.500\,M\,C _2 H _5 OH ( aq )$ and $0.25\, M\, KBr ( aq )$
$B.$ $0.100\,M\,K _4\left[ Fe ( CN )_6\right]$ (aq) and $0.100\, M$ $FeSO _4\left( NH _4\right)_2 SO _4$ (aq)
$C.$ $0.05 \,M\, K _4\left[ Fe ( CN )_6\right]( aq )$ and $0.25\, M\, NaCl$ (aq)
$D.$ $0.15\, M\, NaCl ( aq )$ and $0.1\, M BaCl _2$ (aq)
$E.$ $0.02\, M\, KCl\, MgCl _{2 .} 6 H _2 O ( aq )$ and $0.05\, M$ $KCl ( aq )$