MCQ
The attractive force between 2 charges is related to the distance between them as
- Ar
- B$\frac{1}{r^2}$
- C$r^{\frac{1}{2}}$
- D$\frac{1}{r}$
✓
Answer
(b) $\frac{1}{r^2}$
Explanation: According to Coulomb's law the force between two charges is inversely proportional to the square of distance between the two charges. So $F \alpha \frac{1}{ r ^2}$.
Explanation: According to Coulomb's law the force between two charges is inversely proportional to the square of distance between the two charges. So $F \alpha \frac{1}{ r ^2}$.
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