MCQ
The best method to prepare cyclohexene from cyclohexanol is by using
- AConc. $HCl \,+$ $ZnCl_2$
- ✓Conc. $H_3PO_4$
- C$HBr$
- DConc. $HCl$

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$\Delta E = - 2.0 \times {10^{ - 18}}\,J\left( {\frac{1}{{n_2^2}} - \frac{1}{{n_1^2}}} \right)$
the wavelength of the light that must be absorbed to excite hydrogen electron from level $n\, = 1$ to level $n\, = 2$ will be: $(h\, = 6.625\times10^{-34}\, J\,s,\, C\, = 3\times10^8\, m\,s^{-1})$
$Xe{F_6}\,\xrightarrow{{ + \,\,Excess\,\,{H_2}O}}\,'X'\, + \,HF$
$Xe{F_6}\,\xrightarrow{{ + 2\,\,\,{H_2}O}}\,'Y'\, + \,HF$
| Column $I$ | Column $II$ |
| $(A)$ $\mathrm{O}_2^{-} \rightarrow \mathrm{O}_2+\mathrm{O}_2{ }^{2-}$ | $(p)$ redox reaction |
| $(B)$ $\mathrm{CrO}_4{ }^{2-}+\mathrm{H}^{+} \rightarrow$ | $(q)$ one of the products has trigonal planar structure |
| $(C)$ $\mathrm{MnO}_4^{-}+\mathrm{NO}_2^{-}+\mathrm{H}^{+} \rightarrow$ | $(r)$ dimeric bridged tetrahedral metal ion |
| $(D)$ $\mathrm{NO}_3^{-}+\mathrm{H}_2 \mathrm{SO}_4+\mathrm{Fe}^{2+} \rightarrow$ | $(s)$ disproportionation |