MCQ
The bond angle in carbon tetrachloride is approximately .............. $^o$
- A$90$
- ✓$109$
- C$120$
- D$180$
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$HSO_4^- = 1.2 \times 10^{- 2} ,H_2PO_4^- = 6.3 \times 10^{-8} ,$$HCO_3^- = 4.7 \times 10^{-11}$