MCQ
The bond angle in $s{p^2}$ hybridisation is
- A${180^o}$
- ✓${120^o}$
- C${90^o}$
- D${109^o}2'$
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$C{H_3}CHBrC{H_2}C{H_3}\xrightarrow{{alc.\,KOH}}$
$(i)$ $C{H_3}CH = CHC{H_3}$ (major product)
$(ii)$ $C{H_2} = CHC{H_2}C{H_3}$ (minor product)
