MCQ
The bond order for $\text{O}^+_2,\text{C}_2$ are :
- ✓$2.5, 2$
- B$2, 3$
- C$3, 2$
- D$1.5, 2.0$
✓
Answer
Correct option: A.
$2.5, 2$
$\text{O}^+_2$ has bond order $2.5$
$\text{B.O.}=\frac12(10-5)=\frac52$ In $\ce{C_2(12)}$
$\text{B.O.}=\frac12(8-4)=2$
$\text{B.O.}=\frac12(\text{N}_\text{b}-\text{N}_\text{a})$ where $\ce{N_b}$ is bonding and $\ce{N_a}$ is antibonding electrons.
$\text{B.O.}=\frac12(10-5)=\frac52$ In $\ce{C_2(12)}$
$\text{B.O.}=\frac12(8-4)=2$
$\text{B.O.}=\frac12(\text{N}_\text{b}-\text{N}_\text{a})$ where $\ce{N_b}$ is bonding and $\ce{N_a}$ is antibonding electrons.
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