MCQ
The bond order in $CO_3^{2 - }$ ion between $C - O$ is
- A$0$
- B$0.88$
- ✓$1.33$
- D$2$
Bond order $ = \frac{{{\rm{Total \,number\,of \,bonds \,between \,atoms}}}}{{{\rm{Total\, number\, of \,resonating \,structure}}}}$
$ = \frac{{1 + 1 + 2}}{3} = \frac{4}{3} = 1.33$.
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Reason : Cuprous ion $(Cu^+)$ is colourless whereas cupric ion $(Cu^{2+})$ is blue in the aqueous solution.
$C{O_{(g)}} + \frac{1}{2}{O_{2(g)}} \to C{O_{2(g)}}$
How are $\Delta E$ and $\Delta H$ releated for the reaction?
