MCQ
The bond order in $N_2^ + $ ion is
  • A
    $1$
  • B
    $2$
  • $2.5$
  • D
    $3$

Answer

Correct option: C.
$2.5$
(c) ${\rm{B}}{\rm{.O}}{\rm{.}} = \frac{{{\rm{No}}{\rm{. of }}{N_b} - {\rm{No}}{\rm{. of }}{N_a}}}{2}$$ = \frac{5}{2} = 2.5$.

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