MCQ
The bond order in $N_2^ + $ ion is
- A$1$
- B$2$
- ✓$2.5$
- D$3$
✓
Answer
Correct option: C.
$2.5$
(c) ${\rm{B}}{\rm{.O}}{\rm{.}} = \frac{{{\rm{No}}{\rm{. of }}{N_b} - {\rm{No}}{\rm{. of }}{N_a}}}{2}$$ = \frac{5}{2} = 2.5$.
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