MCQ
The bond order of $He_2^ + $ molecule ion is
- A$1$
- B$2$
- ✓$0.5$
- D$0.25$
$B.O. $ $= \frac{{2 - 1}}{2} = \frac{1}{2} = 0.5$.
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$N_{2}=3.0 \times 10^{-3} M$
$O_{2}=4.2 \times 10^{-3} M$
and $N O=2.8 \times 10^{-3} M$
in a sealed vessel at $800 \,K$ and $1$ $atm$ pressure.........$atm$ will be $K_{p}$ for the given reaction?
$N_{2}(g)+O_{2}(g) \rightleftharpoons 2 N O(g)$
${C_2}{H_{4(g)}} + {H_{2(g)}} \rightleftharpoons {C_2}{H_{6(g)}}\,;$
$\Delta H = -32.7\,Kcal$ carried out is a vessel, the equilibrium concentration of $C_2H_4$ can be increased by