MCQ
The collecting agent in froth floatation process is:
- ✓Sodium ethyl xanthate.
- BPine oil.
- CLime.
- DWater.
✓
Answer
Correct option: A.
Sodium ethyl xanthate.
Collectors either chemically bond $($chemisorption$)$ on a hydrophobic mineral surface, or adsorb onto the surface through physisorption.
Collectors increase the natural hydrophobicity of the surface, increasing the separability of the hydrophobic and hydrophilic particles.
The collecting agent in froth floatation process is sodium ethyl xanthate.
Pine oil is also added in froth floatation but as frother.
Collectors increase the natural hydrophobicity of the surface, increasing the separability of the hydrophobic and hydrophilic particles.
The collecting agent in froth floatation process is sodium ethyl xanthate.
Pine oil is also added in froth floatation but as frother.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which of the following is not a consequence of the Lanthanoid contraction?
Indigestible carbohydrate, which is also a constituent of our diet, is
According to Raoult's law the relative lowering of vapour pressure of a solution of volatile substance is equal to
If two liquids $A$ and $B$ form minimum boiling azeotrope at some specific composition then $......$
→Identify the correct reactivity order for $E_2$ reaction with alc. $KOH$
→In the given reaction :
→$\begin{array}{*{20}{c}}
{\,\,\,\,\,OH\,\,\,\,\,\,\,OH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{C{H_3} - CH - C - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}\xrightarrow{{HI{O_4}}}(a) + (b)$
$(a)$ and $(b)$ respectively be :
Given below are two statements :
→Statement $I$ : The higher oxidation states are more stable down the group among transition elements unlike p-block elements.
Statement $II$ : Copper can not liberate hydrogen from weak acids.
In the light of the above statements, choose the correct answer from the options given below :
Limiting molar conductivity of $CH_3COOH$ (i.e. $\Lambda _{m\,(C{H_3}COOH)}^o$ is equal to
→In a first order reaction, the concentration of the reactant, decreases from $0.8\, M$ to $0.4\, M$ in $15 $ minutes. The time taken for the concentration to change from $0.1 \,M$ to $ 0.025\, M$ is .......... $\min.$
→When $10\,g$ of a non-volatile solute is dissolved in $100\,g$ of benzene, it raises boiling point by ${1\,^o}C$ then molecular mass of the solute is ....... $g.$ $({K_b}$ for benzene $=2.53\,\,k-m^{-1}$)
→