Download App

The d & f Block Elements — Chemistry STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceChemistryThe d & f Block Elements1 Mark
MCQ
The color of $\mathrm{Cu}^{+}$ compounds is?
  • ✓
    White
  • B
    Blue
  • C
    Orange
  • D
    Yellow
✓

Answer

Correct option: A.
White
$\mathrm{Cu}^{+}$ compounds are generally colourless $($white$).$ The electronic configuration is $3 \mathrm{d}^{10} 4 \mathrm{~s}^0.$ So there is no unpaired electron present in the ion. So the electronic transition between two energy levels $\mathrm{t}_{2 \mathrm{~g}}$ and $\mathrm{e}_{\mathrm{g}} ($responsible for the colour of transition metals$)$ is not possible.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from The d & f Block Elements→The d & f Block Elements — all question types→Chemistry STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

$\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\ 
  {\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\ 
  {C{H_3} - C - C{H_2} - C{H_2} - C - H} 
\end{array}$ $\xrightarrow[\Delta ]{{NaOH}}$ Product
→
Which of the following combinations can be used for the preparation of cis vic diol?
→
The correct order for the wavelength of absorption in the visible region is
→
Ionisation of which of the following will be maximum in water
→
The rate constant is given by the equation $k = pz{e^{ - E/RT}}$. Which factor should register a decrease for the reaction to proceed more rapidly
→
Concentrated $H_2SO_4$ is not used to prepare $HBr$ from $KBr$ because it
→
In the reaction sequence, $[X]$ is ketone :

$[X]$ $\xrightarrow{{KMn{O_4}/\mathop O\limits^\Theta  H/\Delta }}$ $\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {HOOC - {{(C{H_2})}_3} - CH - COOH} 
\end{array}} 
\end{array}} 
\end{array}$

$[X]$ will be:

→
The nitrogen containing compound produced in the reaction of $\mathrm{HNO}_3$ with $\mathrm{P}_4^{\prime} \mathrm{O}_{10}$

($A$) can also be prepared by reaction of $\mathrm{P}_4$ and $\mathrm{HNO}_3$

($B$) is diamagnetic

($C$) contains one $\mathrm{N}-\mathrm{N}$ bond

($D$) reacts with $\mathrm{Na}$ metal producing a brown gas

→
Which of following is correct ?
→
$\begin{array}{*{20}{c}}
  {Ph - C - C{H_3}} \\ 
  {||\,\,\,} \\ 
  {O\,\,\,\,} 
\end{array}$ $\xrightarrow[{(ii)\,\Delta }]{{(i)\,aq.\,{K_2}C{O_3}}}$ Product is
→