MCQ
The complex that can show fac - and Mer - isomer is :
  • A
    $\left[ Pt \left( NH _3\right)_2 Cl _2\right]$
  • $\left[ Co \left( NH _3\right)_3\left( NO _2\right)_3\right]$
  • C
    $\left[ Co \left( NH _3\right)_4 Cl _2\right]^{+}$
  • D
    $\left[ CoCl _2( en )_2\right]$

Answer

Correct option: B.
$\left[ Co \left( NH _3\right)_3\left( NO _2\right)_3\right]$
B

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Equilibrium constant of a reaction is related to
An important insecticide is obtained by the action of chloral on chlorobenzene. It is
Which one of the following indicates the correct order of atomic size
The relationship among the following pairs of isomers is
Which of the following oxy acids of phosphorus is a reducing agent and monobasic
Assertion : Acylation of amines gives a monosubstituted product whereas alkylation of amines gives polysubstituted product.
Reason : Acyl group sterically hinders the approach of further acyl groups
The $IUPAC$ name of $\begin{array}{*{20}{c}}
  {C{H_2}C{H_3}\,\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3} - C{H_2} - C - CH - C{H_2} - {{(C{H_2})}_2} - C{H_3}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {\,\,\,\,C{H_2}C{H_{3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}} 
\end{array}$ is
At $298\, K$ the $emf$ of cell is ............ $\mathrm{V}$

$\operatorname{P}t|{{H}_{{{2}_{\left( 2\,atm \right)}}}}|H_{\left( 0.02\,M \right)}^{\oplus }||H_{\left( 0.1\,M \right)}^{\oplus }|{{H}_{{{2}_{\left( 1\,atm \right)}}}}|Pt$

Major product obtained in following reaction is : 
The de-Broglie's wavelength of an electron in the $4^{\text {th }}$ orbit is . . . . . . . . $\pi a_0 .\left(a_0=\right.$ Bohr's radius)