MCQ
The complex that violates the Sidgwicks's rule of $EAN$ is
- APotassium ferrocyanide
- BHexamine cobalt $(III)$ Chloride
- ✓Tetramine copper $(II)$ sulphate
- DPotassium dichlorodioxalato cobaltate $(III)$
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$C{H_3}C{H_2}C{H_2}Br$ $\xrightarrow{{KOH(alc.)}}\,(A)\,\xrightarrow{{HBr}}(B)\,$ $\xrightarrow{{KOH(aq.)}}(C)$ The product $(C)$ is
$[A]$ $HClO_4$ is more acidic than $\mathrm{HClO}$ because of the resonance stabilization of its anion
$[B]$ $HClO_4$ is formed in the reaction between $Cl_2$ and $H_2 O$
$[C]$ The central atom in both $HClO_4$ and $HClO$ is $s p^3$ hybridized
$[D]$ The conjugate base of $HClO_4$ is weaker base than $H_2 O$