MCQ
The compound $1, 2-$butadiene has
  • A
    Only $sp$ hybridized carbon atoms
  • B
    Only $s{p^2}$ hybridized carbon atoms
  • C
    Both $sp$ and $s{p^2}$ hybridized carbon atoms
  • $sp,\,\,s{p^2}$ and $s{p^3}$ hybridized carbon atoms

Answer

Correct option: D.
$sp,\,\,s{p^2}$ and $s{p^3}$ hybridized carbon atoms
(d) $\mathop {C{H_2}}\limits^{s{p^2}} = \mathop C\limits^{sp} = \mathop {CH}\limits^{s{p^2}} -\mathop {C{H_3}}\limits^{s{p^3}\,\,} $ $1, 2-$butadiene.

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$(I)$ $\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\ 
  {C{H_3} - C{H_2} - O - S - C{F_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} 
\end{array}$

$(II)$ $CH_3-CH_2-O-TsCl$

$(III)$ $\begin{array}{*{20}{c}}
  {C{H_3} - CH - C{H_3}} \\ 
  {|\,\,\,\,} \\ 
  {OH\,} 
\end{array}$

$(IV)$ $\begin{array}{*{20}{c}}
  {C{H_3} - CH - OH} \\ 
  | \\ 
  {{C_6}{H_5}} 
\end{array}$