MCQ
The compound ${C_3}{H_4}$ has a triple bond, which is indicated by its reaction with
- ABromine water
- BBayer's reagent
- CFehling solution
- ✓Ammonical silver nitrate
✓
Answer
Correct option: D.
Ammonical silver nitrate
d
(d) $\underset{\text{Propyne}}{\mathop{C{{H}_{3}}-C\equiv C-H}}\,\,+\underset{\text{Ammonical}}{\mathop{AgN{{O}_{3}}}}\,\to \underset{\begin{smallmatrix}
\text{Siver}\,\text{salt}\,\text{of} \\
\,\,\,\text{Propyne}
\end{smallmatrix}}{\mathop{C{{H}_{3}}-C\equiv C-Ag}}\,$
(d) $\underset{\text{Propyne}}{\mathop{C{{H}_{3}}-C\equiv C-H}}\,\,+\underset{\text{Ammonical}}{\mathop{AgN{{O}_{3}}}}\,\to \underset{\begin{smallmatrix}
\text{Siver}\,\text{salt}\,\text{of} \\
\,\,\,\text{Propyne}
\end{smallmatrix}}{\mathop{C{{H}_{3}}-C\equiv C-Ag}}\,$
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