Question
The compound that is chiral is
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$kJ\,mol ^{-1}$ (Nearest integer)
Given : $\Delta_{ dis } H _{ Cl _{2(g)}}^{\circ}=240\,kJ\,mol ^{-1}$.
$\Delta_{ eg } H _{ Cl _{(g)}}^{\circ}=-350\,kJ\,mol ^{-1}$,
$\Delta_{ hyd } H _{ Cl i _{( j )}^{\circ}}^{\circ}=-380\,kJ\,mol ^{-1}$
(1)${H_2} \to {H^ \bullet } + {H^ \bullet }$
(2)$B{r_2} \to B{r^ \bullet } + B{r^ \bullet }$
(3)$B{r^ \bullet } + HBr \to {H^ \bullet } + B{r_2}$
(4)${H^ \bullet } + B{r_2} \to HBr + B{r^ \bullet }$
(5)$B{r^ \bullet } + B{r^ \bullet } \to B{r_2}$