MCQ
The compound that will react most readily with $ NaOH $ to form methanol is
  • ${(C{H_3})_4}{N^ + }{I^ - }$
  • B
    $C{H_3}OC{H_3}$
  • C
    ${(C{H_3})_3}{S^ + }{I^ - }$
  • D
    ${(C{H_3})_3}Cl$

Answer

Correct option: A.
${(C{H_3})_4}{N^ + }{I^ - }$
a
The reaction is expected to be most spontaneous when there is leaving the group.

The $CH _3$ group with positive $N$ atom is more electron deficient and to more reactive towards the nucleophile.

$\left( CH _3\right)_4 N ^{+} I ^{-}+ OH ^{-} \stackrel{ SN ^2}{\longrightarrow} CH _3 OH$

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