MCQ
The compound that will react most readily with $ NaOH $ to form methanol is
- ✓${(C{H_3})_4}{N^ + }{I^ - }$
- B$C{H_3}OC{H_3}$
- C${(C{H_3})_3}{S^ + }{I^ - }$
- D${(C{H_3})_3}Cl$
The $CH _3$ group with positive $N$ atom is more electron deficient and to more reactive towards the nucleophile.
$\left( CH _3\right)_4 N ^{+} I ^{-}+ OH ^{-} \stackrel{ SN ^2}{\longrightarrow} CH _3 OH$
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$\mathrm{E}_{\mathrm{n}}=$ Total energy, $\mathrm{K}_{\mathrm{n}}=$ Kinetic energy, $\mathrm{V}_{\mathrm{n}}=$ Potential energy , $\mathrm{r}_{\mathrm{n}}=$ Radius of $\mathrm{n}^{\text {th }}$ orbit
Match the following:
| Column $I$ | Column $II$ |
| $(A)$ $\mathrm{V}_{\mathrm{n}} / \mathrm{K}_{\mathrm{n}}=$ ? | $(P)$ $0$ |
| $(B)$ If radius of $n^{\text {th }}$ orbit $\propto E_n^x, x=$ ? | $(Q)$ $-1$ |
| $(C)$ Angular momentum in lowest orbital | $(R)$ $-2$ |
| $(D)$ $\frac{1}{\mathrm{r}^{\mathrm{n}}} \propto \mathrm{Z}^{\mathrm{y}}, \mathrm{y}=$ ? | $(S)$ $1$ |