MCQ
The compound which will give negative iodoform test is
- A$C{H_3}CHO$
- B$C{H_3}C{H_2}OH$
- CIsopropyl alcohol
- ✓Benzyl alcohol
${C_6}{H_5} - C{H_2} - OH\xrightarrow{{NaOH/{I_2}}}{\text{No}}\,\,{\text{yellow}}\,\,ppt.$
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$(i)\, [Co(en)_2(Ox)]^+$
$(ii)\, [Fe(Trien)(Ox)]^+$
$(iii)\, [Ca(EDTA)]^{-2}$
$(iv)\, [Pt(Ox)_2 (H_2O)_2]$

$(i)$ $0.10\, \mathrm{M} \,\mathrm{Ba}_{3}\left(\mathrm{PO}_{4}\right)_{2}$ $(ii)$ $0.10\, \mathrm{M}\, \mathrm{Na}_{2} \mathrm{SO}_{4}$ $(iii)$ $0.10\, \mathrm{M}\, \mathrm{KCl}$ $(iv)$ $0.10 \,\mathrm{M} \,\mathrm{Li}_{3} \mathrm{PO}_{4}$