MCQ
The compound which will give negative iodoform test is
- A$C{H_3}CHO$
- B$C{H_3}C{H_2}OH$
- CIsopropyl alcohol
- ✓Benzyl alcohol
${C_6}{H_5} - C{H_2} - OH\xrightarrow{{NaOH/{I_2}}}{\text{No}}\,\,{\text{yellow}}\,\,ppt.$
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In the given reaction what will be the product
| Experiment |
$[A]$ (in $mol\, L^{-1})$ |
$[B]$ (in $mol\, L^{-1})$ |
Initial rate of reaction (in $mol\, L^{-1}\,min^{-1})$ |
| $I$ | $0.10$ | $0.20$ | $6.93 \times {10^{ - 3}}$ |
| $II$ | $0.10$ | $0.25$ | $6.93 \times {10^{ - 3}}$ |
| $III$ | $0.20$ | $0.30$ | $1.386 \times {10^{ - 2}}$ |
The time(in minutes) required to consume half of $A$ is